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The Hyperbolic Form of a Solution

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Figure (2.8a) shows a section of the transmission line having a length ℓ. It is fed by a voltage source, with Zg internal impedance. The general solutions for the line voltage and line current of the wave equation (2.1.37) are

(2.1.55)

At any section on the line, its characteristic impedance Z0 relates the line voltage and line current . So the constants A2, B2 are related to the constants A1 and B1. In Fig (2.8a), the point P on the line is located at a distance x from the source end, i.e. at a distance d = (ℓ − x) from the load end. The load is located at d = 0, and the source is located at d = − ℓ. The , and are the input voltage and the input current at the port‐aa, i.e at x = 0. At x = ℓ, i.e. at the port‐bb, and are the load end voltage and current, respectively. The ideal voltage generator has the internal impedance, Zg = 0, i.e. . The phasor form of the line current, from equations (2.1.32b) and (2.1.55a), is written below:


Figure 2.8 Transmission line circuit. The distance x is measured from the source end; whereas the distance d is measured from the load.

(2.1.56)

On comparing the coefficients of sinh(γx) and cosh(γx), of equations (2.1.55b) and (2.1.56), two constants A2 and B2 are determined:

(2.1.57)

The phasor line voltage and line current are written as follows:

(2.1.58)

The constants A1 and B1 are determined by using the boundary conditions at input x = 0 and output x = ℓ.

 At x = 0, the line input voltage is , giving the value of A1:(2.1.59)

At the receiving end, x = ℓ, the load end voltage and current are

(2.1.60)

 At x = ℓ, i.e. at the receiving end, the voltage across load ZL is(2.1.61)

The constant B1 is evaluated on substituting and , from equation (2.1.60), in the above equation:

(2.1.62)

On substituting constants A1 and B1 in equation (2.1.58a), the expression for the line voltage at location P, from the source or load end, is

(2.1.63)

Similarly, the line current at the location P is obtained as follows:

(2.1.64)

At any location P on the line, the load impedance is transformed as input impedance by the line length d = (ℓ − x):

(2.1.65)

Equations (2.1.65a,b) take care of the losses in a line through the complex propagation constant, γ = α + jβ. However, for a lossless line α = 0, γ = jβ and the hyperbolic functions are replaced by the trigonometric functions shown in equation (2.1.65c). It shows the impedance transformation characteristics of d = λ/4 transmission line section.

Equations (2.1.63) and (2.1.64) could be further written in terms of the generator voltage for the case, Zg ≠ 0. Figure (2.8b) shows that at the source end x = 0, the load appears as the input impedance Zin. The sending end voltage is obtained as follows:

, where .

(2.1.66)

The line voltage, in terms of , and ZL, is obtained on substituting equation (2.1.66) in equation (2.1.63):

(2.1.67)

Likewise, from equations (2.1.64) and (2.1.66), an expression for the line current is obtained:

(2.1.68)

The above equations could be reduced to the following equations for a lossless line, i.e. for α = 0, γ = jβ, cosh(jβ) = cos β and sinh(jβ) = j sin β:

(2.1.69)

(2.1.70)

Equation (2.1.65c), for the input impedance, could be obtained from the above two equations. The sending end voltage and current are obtained at the input port – aa, x = 0:

(2.1.71)

(2.1.72)

Likewise, the expressions for the voltage and current at the output port – bb, i.e. at the receiving end for x = ℓ, are obtained:

(2.1.73)

(2.1.74)

Two special cases of the load termination, i.e. the short‐circuited load and the open‐circuited load, are discussed below. The voltage and current distributions on a transmission line for both the cases are also obtained.

Introduction To Modern Planar Transmission Lines

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