Читать книгу Engineering Acoustics - Malcolm J. Crocker - Страница 159
Solution
ОглавлениеWe take the inverse of Eq. (4.3): f = 700(10 m/2595 − 1) = 700 (10 − 1) = 6300 Hz.
We take the inverse of Eq. (4.3): f = 700(10 m/2595 − 1) = 700 (10 − 1) = 6300 Hz.
