Читать книгу Introduction to Mechanical Vibrations - Ronald J. Anderson - Страница 26
1.3.1.1 Linear EOM for a Simple Pendulum
ОглавлениеThe nonlinear differential equation of motion for the pendulum (Equation 1.44) is valid for any range of motion. The difficulty is that we can't solve nonlinear differential equations without resorting to numerical methods. We get around this problem by linearizing the differential equation because we have had courses on how to solve linear differential equations.
To do this, we consider small motions near the stable equilibrium state. Let in Equation 1.44 be replaced by where is a very small angle and is the equilibrium value of . That is,
and, differentiating with the knowledge that is constant, we find
and then
Substituting into Equation 1.44 yields
We can use the trigonometric identity for the sine of the sum of two angles7 to write
We now consider rewriting Equation 1.52 under the condition where is a very small angle. The small angle conditions on the sine and cosine are derived from their Maclaurin's Series expansions. The expansions are
and
If is very small, then higher powers of are much smaller and are negligible8 in the series. We therefore approximate the sine and cosine with
and
Equation 1.52 can then be written as
(1.53)
and the equation of motion (Equation 1.51) becomes
Note the constant term that appears in Equation 1.54. This is the term that was set to zero to determine the equilibrium state (see Equation 1.45) and it is still equal to zero so it can be removed. The equilibrium condition is always a set of constant terms that must be zero for the system not to move and that set of constant terms always reappears in the linearized equation of motion. After removing the equilibrium condition, the linearized equation of motion for the pendulum becomes
(1.55)
This equation is valid for motion about either of the two equilibrium states we found (i.e. with and with ). We write
and
Equation 1.56 will yield oscillating solutions (i.e. vibrations – more to come later) and Equation 1.57 will yield growing exponential solutions, showing that the system really doesn't want to stay in the unstable upright position.