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Solution

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We need to find


Since the geometry is circular, it is easier to work with a cylindrical coordinate system, hence we transform vector to cylindrical coordinates as


Figure 1.13 Path for line integral Example 1.1.


In a cylindrical coordinate system, the differential length along the path is defined as


where r = 2 along the path. So



Figure 1.14 Illustration of surface integral.

RF/Microwave Engineering and Applications in Energy Systems

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