Читать книгу Engineering Acoustics - Malcolm J. Crocker - Страница 106
Solution
ОглавлениеFrom Eq. (3.41) (for an omnidirectional source). Then W = 1.26 × 10−3 watts (the same result as Example 3.8).
Sound intensity measurements do and should give the same result as sound pressure measurements made in a free field.
Far away from omnidirectional sound sources, provided there is no background noise and reflections can be ignored:
(3.49)
and by taking 10 log throughout this equation
(3.50)
where Lp is the sound pressure level, LW is the source sound power level, and r is the distance, in metres, from the source center. (Note we have assumed here that ρc = 415 ≅400 rayls.) If ρc ≅ 400 rayls (kg/m2s), then since I = p2rms/ρc
So,
(3.51)