Читать книгу Engineering Acoustics - Malcolm J. Crocker - Страница 66
Solution
ОглавлениеApplying the boundary conditions w = 0 and at x = 0 in Eq. (2.54) leads to C1 + C3 = 0 and −λ2 C1 + λ2 C3 = 0. These equations are satisfied if C1 = C3 = 0.
Applying the boundary conditions w = 0 and at x = L in Eq. (2.54) yields
C2 sin(λL) + C4 sinh(λL) = 0 and −λ2 C2 sin(λL) + λ2 C4 sinh(λL) = 0. Therefore, nontrivial solutions are obtained when C4 = 0 and sin(λL) = 0, so λ = nπ/L (for n = 1,2,…). Since λ = (ω2 ρS/EI)1/4, we find that the natural frequencies ωn are given by