Читать книгу Applied Biostatistics for the Health Sciences - Richard J. Rossi - Страница 73

1 For values of z between −3.49 and 3.49, the probability that Z≤z is read directly from the table. That is,

2 For z≤−3.50 the probability that Z≤z is 0, and for z≥3.50 the probability that Z≤z is 1.

3 For values of z between −3.49 and 3.49, the probability that Z≥z is

4 For values of z between −3.49 and 3.49, the probability that a≤Z≤b is

Example 2.34

To determine the probability that a standard normal random variable is less than 1.65, which is the area shown in Figure 2.26, look up 1.6 in the left-most column of Table A.2 and 0.05 in the top row of this table, which yields P(Z≤1.65)=0.9505.

Figure 2.26 P(Z≤1.65).

Example 2.35

Determine the probability that a standard normal random variable lies between −1.35 and 1.51 (see Figure 2.27).

Figure 2.27 P(−1.35≤Z≤1.51).

Solutions First, look up the cumulative probabilities for both −1.35 and 1.51 in Tables A.1 and A.2. The probability that Z≤−1.35 and the probability that Z≤1.51 are shown in Figure 2.28.

Figure 2.28 The areas representing P(Z≤1.51) and P(Z≤−1.35).

Subtracting these probabilities yields P(−1.35≤Z≤1.51), and thus,

Example 2.36

Using the standard normal tables given in Tables A.1 and A.2, determine the following probabilities for a standard normal distribution:

1 P(Z≤−2.28)

2 P(Z≤3.08)

3 P(−1.21≤Z≤2.28)

4 P(1.21≤Z≤6.28)

5 P(−4.21≤Z≤0.84)

Solutions Using the normal table in the appendix

1 P(Z≤−2.28)=Φ(−2.28)=0.0113

2 P(Z≥3.08)=1−Φ(3.08)=1−0.9990=0.0010

3 P(−1.21≤Z≤2.28)=Φ(1.81)−Φ(−1.21)=0.9887−0.1131=0.8756

4 P(0.67≤Z≤6.28)=Φ(6.28)−Φ(0.67)=1−0.7486=0.2514

5 P(−4.21≤Z≤0.84)=Φ(0.84)−0=0.7995

The pth percentile of the standard normal can be found by looking up the cumulative probability p100 inside of the standard normal tables given in Appendix A and then working backward to find the value of Z. Unfortunately, in some cases the value of p100 will not be listed inside the table, and in this case, the value closest to p100 inside of the table should be used for finding the approximate value of the pth percentile.

Example 2.37

Determine the 90th percentile of a standard normal distribution.

Solutions To find the 90th percentile, the first step is to find 90100=0.90, or the value closest to 0.90, in the cumulative standard normal table. The row of the standard normal table containing the value 0.90 is given in Table 2.11. Since 0.8997 is the value closest to 0.90 that occurs in the row labeled 1.2 and the column labeled 0.08, the 90th percentile of a standard normal distribution is roughly z=1.2+0.08=1.28.

Table 2.11 An Excerpted Section of the Cumulative Normal Table

Φ(z)=P(Z≤z)
z	0.00	0.01	0.02	0.03	0.04	0.05	0.06	0.07	0.08	0.09
⋮
1.2	0.8849	0.8869	0.8888	0.8907	0.8925	0.8944	0.8962	0.8980	0.8997	0.9015
⋮

The most commonly used percentiles of the standard normal are given in Table 2.12, and a more complete list of the percentiles of the standard normal distribution is given in Table A3. Note that for p < 50 the percentiles of a standard normal are negative, for p = 50 the 50th percentile is the median, and for p > 50 the percentiles of a standard normal are positive.

Table 2.12 Selected Percentiles of a Standard Normal Distribution

p	1	5	10	20	25	50
pth percentile	−2.33	−1.645	−1.28	−0.84	−0.67	0.00
p	75	80	90	95	99	99.9
pth percentile	0.67	0.84	1.28	1.645	2.33	3.09

When X is a normal distribution with μ≠0 or σ≠1, the distribution of X is called a non-standard normal distribution. The standard normal distribution is the reference distribution for all normal distributions because all of the probabilities and percentiles for a non-standard normal can be determined from the standard normal distribution. In particular, the following relationships between a non-standard normal with mean µ and standard deviation σ and the standard normal can be used to convert a non-standard normal value to a Z-value and vice versa.