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3.9.6 Pressure dependence of equilibrium constant

Оглавление

Since


and


then

(3.97)

If ΔVr does not depend on pressure, this equation can be integrated to obtain:

(3.97a)

This assumption will be pretty good for solids because their compressibilities are very low, but slightly less satisfactory for reactions involving liquids (such as dissolution), because they are more compressible. This assumption will be essentially totally invalid for reactions involving gases, because their volumes are highly pressure-dependent.

Geochemistry

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